Frenchman Simon Pagenaud takes pole position at Indianapolis 500

Simon Pagneaud (Penske) took pole position on Sunday for the 103rd edition of the Indianapolis 500 which will take place on May 26. The French, crowned IndyCar champion in 2016, finished first in the « Fast Nine », the qualifying session reserved for the nine best drivers of the day on Saturday. He had set the third fastest time the day before.

Pagenaud, 35, completed his four laps of the famous Indianapolis Oval Circuit in 2 min 36 sec 5271, an average speed of 370.1 km / h. He beat two drivers from the Ed Carpenter team, the Americans Ed Carpenter and Spencer Pigot. Pagenaud had finished 6th of the Indianapolis 500 miles in 2018, his best result in one of the most prestigious races in motorsport. Last week he won the Indianapolis Grand Prix for the third time, partly set on the « Indy » oval circuit.


Grosjean: « On oval, I have to learn everything »

10/07/2021 At 7:45 AM

« This pole is really something special, it’s incredible. Winning last week here was strong, but getting pole is crazy« said Pagenaud. « We are in a good dynamic, we have the best car, the best engine, but the 500 miles is a very long race, anything can happen« , he warned.

We have to go back to 1920 to find traces of the last Frenchman, Gaston Chevrolet, to win in Indianapolis.


Pagenaud turns the page Penske and joins Meyer

09/27/2021 At 3:21 PM


Palou, new champion, new generation

09/27/2021 At 05:41

Laisser un commentaire